When i print the number using the format specifier %llu, what is printed is %lu. I also compare the value i get from atoll or strtoll with the expected value and it is smaller, which i guess. I found %llu in another question but they say it is for linux only.
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% — starts a conversion specification; Please use the correct format specifier %zu, although %llu is a valid format spec. I need to print a ulonglong value (unsigned __int64).
I use diab c compiler for compiling my application code to run on.
L — the length modifier, l means [unsigned] long int; In translation phase 6, the multibyte character sequences. It is unclear why you need to compute the length of an array that you just defined to have index elements. For most other platforms you'd use %lld for printing a long long.
That is because %llu doesn't work properly under windows and %d can't handle 64 bit integers. None seems to be correct. (and %llu if it's unsigned). Prints llu on my machine.
I tried, %l, %ld, %ll.
I suggest using priu64 instead and you'll find it's portable to linux as well. What is the format specifier that i should use in print statements? Powiat łukowski to powiat w którym rejestracje zaczynają się od llu. This is standarized in c99.
%lu is a valid conversion specification, %ul is not. Adjacent string literals are concatenated, from section 6.4.5 string literals of the c99 standard: What format should i use in printf ?
