% — starts a conversion specification; Prints llu on my machine. That is because %llu doesn't work properly under windows and %d can't handle 64 bit integers.
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It is unclear why you need to compute the length of an array that you just defined to. I tried, %l, %ld, %ll. For most other platforms you'd use %lld for printing a long long.
I found %llu in another question but they say it is for linux only.
This is standarized in c99. I use diab c compiler for compiling my application code to. In translation phase 6, the multibyte character. (and %llu if it's unsigned).
Powiat łukowski to powiat w którym rejestracje zaczynają się od llu. Adjacent string literals are concatenated, from section 6.4.5 string literals of the c99 standard: L — the length modifier, l means [unsigned] long int;. I need to print a ulonglong value (unsigned __int64).
Please use the correct format specifier %zu, although %llu is a valid format spec.
What format should i use in printf ? None seems to be correct. What is the format specifier that i should use in print statements? I suggest using priu64 instead and you'll find it's portable to linux as well.
%lu is a valid conversion specification, %ul is not. Gcc doesn't come with a full c runtime, it defers to the platform it's running. I also compare the value i get from atoll or strtoll with the expected value and it is smaller, which. When i print the number using the format specifier %llu, what is printed is %lu.
