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Step by step video, text & image solution for two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other. Not the question you're searching for? The ratio of their speeds is.

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Two trains running in opposite directions cross a man standing on the platform in 27 sec and 17 sec, respectively and they cross each other in 23 sec. The ratio of their speeds is. ∴ 27x+17y x+y =23 27x+17y= 23x+23y.

Train a crosses a platform in 54 seconds and train b takes '10x' seconds to cross the same platform.

Then, length of the first train = 27 x metres and length of the second train = 17 y metres. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. Let the speeds of the two trains be x m/sec and y m/sec respectively. If a train t1 takes 27 sec to cross the man which is more than the time taken by train t2 (17 sec) then how can the speed of train t1 is greater than the speed of train t2?

Two trains, train a and train b, have lengths of x meters and (x + 50) meters respectively. Train a crosses an electric. The ratio of the speed of train a to train b is 5 : (27 x + 17 y) / (x + y) = 23 => 27 x.

Two trains running in opposite directions cross a man standing on the pla.

Trains a and b can cross a pole in 'x' seconds and 15 seconds respectively. Let the speeds of the two trains be x m/sec and y m/sec. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other.

Two trains running in opposite direction.