%lu is a valid conversion specification, %ul is not. % — starts a conversion specification; What format should i use in printf ?
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When i print the number using the format specifier %llu, what is printed is %lu. Prints llu on my machine. Powiat łukowski to powiat w którym rejestracje zaczynają się od llu.
For most other platforms you'd use %lld for printing a long long.
I need to print a ulonglong value (unsigned __int64). None seems to be correct. I also compare the value i get from atoll or strtoll with the expected value and it is smaller, which. It is unclear why you need to compute the length of an array that you just defined to.
In translation phase 6, the multibyte character. This is standarized in c99. (and %llu if it's unsigned). L — the length modifier, l means [unsigned] long int;.
What is the format specifier that i should use in print statements?
I tried, %l, %ld, %ll. I found %llu in another question but they say it is for linux only. I suggest using priu64 instead and you'll find it's portable to linux as well. I use diab c compiler for compiling my application code to.
Gcc doesn't come with a full c runtime, it defers to the platform it's running. Adjacent string literals are concatenated, from section 6.4.5 string literals of the c99 standard: That is because %llu doesn't work properly under windows and %d can't handle 64 bit integers. Please use the correct format specifier %zu, although %llu is a valid format spec.
